I've seen some numbers kicked around elsewhere, but what is the actual front cross-sectional area and drag coefficient?
D = Cd * r * V ^2 * A / 2
At terminal velocity, D = W. Solving for the velocity, we obtain the equation
V = sqrt ( (2 * W) / (Cd * r * A) )
The terminal velocity equation tells us that an object with a large cross-sectional area or a high drag coefficient falls slower than an object with a small area or low drag coefficient. A large flat plate falls slower than a small ball with the same weight. If we have two objects with the same area and drag coefficient, like two identically sized spheres, the lighter object falls slower. This seems to contradict the findings of Galileo that all free falling objects fall at the same rate with equal air resistance. But Galileo's principle only applies in a vacuum, where there is NO air resistance and drag is equal to zero.

So it would be 0 d v
0= airless
d= drag
v=vaccuum
zero drag= more faster!
* Subsonic: Ma < 1
* Sonic: Ma = 1
* Transonic: 0.8 < Ma < 1.3
* Supersonic: 1.2 < Ma < 5
* Hypersonic: Ma > 5
[B
]For the GT drag coefficient is 0.28Cd[/B]