A quick analysis of second gear acceleration ... a good indicator in my experience for street performance, as well as seat-of-the pants "feel" ... the subject of this thread :biggrin
Let's compare the Ford GT to a Shelby GT500 with 4.10's swapped in :
Motor Torque : Ford GT = 500 lb-ft, Shelby GT500 = 480 lb-ft
2nd Gear Ratio : Ford GT = 1.71, Shelby GT500 = 1.78
Final Drive Ratio : Ford GT = 3.36, Shelby GT500 = 4.10 (swap)
Tire Diameter : Ford GT = 1.21 ft, Shelby GT500 = 1.12 ft
Weight : Ford GT = ~3500, Shelby GT500 = ~3900
Accelerating force at road/tire interface is found by mulitplying motor torque by gear ratios (selected gear and final drive), and dividing by tire diameter :
Accelerating Force : Ford GT = 2374 lbs, Shelby GT500 = 3128 lbs
Including vehicle weight, the resulting acceleration numbers (strange units, because I'm using pounds for mass rather than slugs):
Acceleration : Ford GT = 0.678, Shelby GT500 = 0.802
So ... there's no question that the GT500 with 4.10's will pull much harder than the GT in second gear (assuming no traction limits, of course).
But what will the top speed be, in second gear for the GT500 with 4.10's? With a redline of 6250 rpm, the top speed should be about 69mph (tire circumference of 7.1 feet).
Now the GT will obviously pull harder in first gear, than the GT500 will pull in second gear. And the GT500 will spend first pretty quickly with 4.10's swapped in, whereas the GT takes first all the way to 60 mph.
More to follow ...