Dyno Conversion Rate's

[Awsum GT]

Can someone tell me what you would multiply the rear wheel hp and torque by to get close to the hp and torque at the engine?

 

[dbk]

People on the GT team have told me that you lose a bit over 7% through the driveline, so I use that math.

 

[Fords4life351]

the transaxle on the Ford GT must be very efficient because on most "normal" cars the loss is between 10-20 percent depending on transmisson.

 

[Awsum GT]

I was told about 13% plus 6% for excess outside heat - summer heat. I have been told it is about 15% on the Vipers.

 

[Silverbullitt]

People on the GT team have told me that you lose a bit over 7% through the driveline, so I use that math.

That means you could divide rwhp by.93 to get flywheel hp.

 

[barondw]

10-15% is the number usually used for power lose. The larger the loss factor the higher the crank or flywheel rating of HP and/or Torque.

If 15% loss and 540 rwhp the calculation is: 545/.85 (100% - 15%) = 635 crank/flywheel

If 10% loss and 540 rwhp: 540/.90 = 600 crank/flywheel.

Formula obviosuly can be used for any calculation just changing the factor and dyno results.

Use the SAE corrected dyno number and the smoothing set to #5.

Dave

 

[dbtgt]

Great article, Centerpunch! :thumbsup